Question

Cine raspunde ii dau toate punctele mele>60 de puncte pana maine
1)Calculati:
/>a) √45:3√5
b) -√8:√8:v8
c) √2 x √0,3:√0,6
d) √5 x √2:√5 x (-√2)

2) Calculati:
a) 4,4√2:2√2
b) -√2 + 3 x √2
c) √3-√18:3
d) 0,4√2-5 x 3√2+12,6√2

3) Calculati:
a) 7 la puterea 2 - 3 la puterea 2+(-5) laputerea 2
b) 0 la puterea 100+(-√7) la puterea 3+√243
c) √1,44-(1,2) la puterea 2
d) √3 la puterea 2+4 la puterea 2-√5 la puterea 2
4) Calculati:a)[3 supra √3-(0,4+√3)] x 10b) [-3√5-(1 supra 2-2√5)] x 2c) √(√3-√2) la puterea 2-(√3-√2)

5) Calculati:
a) 2 la puterea -1+3 la puterea -1
b) (-√2) la puterea -2+(√3) la puterea -2
c) √27 x (√3) la puterea -3+1
d) [(2+3) la puterea -1+1 spura √5]:(1+√5)

6) Calculati:
a) 4-4(2√2-4 supra √2)
b) [-√75-4(√3-2√3)]:1 la puterea 50
c) 5-5 x [(√6+√3):√3-√2]
d) -5+5 x {2+√2[√2+3(√27-3√3)]+3 la puterea 0}:(-1) la puterea 5.

Answer 1

a) √45:3√5=√(9x5):3√5=3√5/3√5=1
b) -√8:√8:√8=-√8/√8:√8=-1:√8=-1/√8=-√8/√8²=-√8/8=-2√2/8=-√2/4
c) √2 x √0,3:√0,6=√(2x0,3):√0,6=√0,6/√0,6=1
d) √5 x √2:√5 x (-√2)=√10:(-√10)=-√10/√10=-1

2) Calculati:
a) 4,4√2:2√2=4,4√2/2√2=4,4/2=2,2
b) -√2 + 3 x √2=-√2+3√2=2√2
c) √3-√18:3=√3-√6
d) 0,4√2-5 x 3√2+12,6√2=0,4√2-15√2+12,6√2=13√2-15√2=-2√2

3) Calculati:
a) 7 ² - 3²+(-5)²=49-9+25=40+25=65
b) 0¹⁰⁰+(-√7)³+√243=0+7√7+√3⁵=7√7+9√3
c) √1,44-(1,2)²=√(1,44-1,44)=0
d) √3²+4²-√5²=3+16-5=19-5=14
4) Calculati:a)[3/√3-(0,4+√3)] x 10=[3√3/3-4/10-√3]x10=
[(3√3x10-4x3-√3x30)/30]x10=
[(30√3-12-30√3)/30]x10=
-12/30x10/1=-12/3=-4
b) [-3√5-(1/( 2-2√5)] x 2=
[-3√5-(2+2√5)/(4-20)]x2=
[-3√5-(2+2√5)/-16]x2=
[-3√5+2(1+√5)/16]x2=
[-3√5+(1+√5)/8]x2=
[(-3√5x8+1+√5)/8]x2=
[(-24√5+1+√5)/8]x2=
(-23√5+1)/8x2/1=(-23√5+1)4

c) √(√3-√2)²-(√3-√2)=3-2√6+2-√3+√2=5-2√6-√3+√2

5) Calculati:
a) 2⁻¹+3⁻¹=1/2+1/3=(3+2)/6=5/6
b) (-√2)⁻²+(√3)⁻²=1/(-√2)²+1/√3²=1/2+1/3=(3+2)/6=5/6
c) √27 x (√3)⁻³+1=3√3x1/√3³+1=3√3/3√3+1=1+1=2
d) [(2+3)⁻¹+1/√5]:(1+√5)=[(5)⁻¹+1/√5]:(1+√5)=
[1/5+√5/5[:(1+√5)=
[(1+√5)/5]x1/(1+√5)=1/5

6) Calculati:
a) 4-4(2√2-4/√2)=4-8√2+16/√2=4-8√2+16√2/2=4-8√2+8√2=4
b) [-√75-4(√3-2√3)]:1⁵⁰=[-5√3-4√3+8√3]:1=-√3
c) 5-5 x [(√6+√3):√3-√2]=5-5x[(√6+√3)(√3+√2)/(3-2)=
5-5x(√18+√12+3+√6)=
5-5x(3√2+2√3+3+√6)=
5-15√2-10√3-15-5√6=
-5(3√2+2√3+√6+4)
d) -5+5 x {2+√2[√2+3(√27-3√3)]+3°}:(-1)⁵=
-5+5x{2+√2[√2+3(3√3-3√3)]+1}:(-1)=
-5+5x{2+√2[√2+3x0]+1}:(-1)=
-5+5x{2+√2[√2+1}:(-1)=
-5+5x{2+2√2}:(-1)=
-5-5x{2+2√2}=
-5-10-10√2=
-15-10√2=-5(3+2√2)