Question

CINE SE PRICEPE LA GEOMETRIE????DAU 70 DE PUNCTE VA ROG AM NEVOIE DE REZOLVARE PANA DISEARA!!!!

Answer 1

pt ultima problema: rezolvare: 
- cateta opusa unghiului de 30 de grade este egala cu jumatate din ipotenuza 
$AB=\frac{BC}{2}$
$\frac{BC}{2} =12 =\ \textgreater \ BC=12*2=24$
$sin 60 = \frac{cateta opusa}{ipotenuza} =\ \textgreater \ \frac{AC}{BC} = \frac{ \sqrt{3} }{2}$
$\frac{AC}{24} = \frac{ \sqrt{3} }{2} =\ \textgreater \ 2AC=24 \sqrt{3} =\ \textgreater \ AC= \frac{24 \sqrt{3} }{2} =\ \textgreater \ AC=12 \sqrt{3}$

$A = \frac{AB*AC}{2} = \frac{12 \sqrt{3} *12}{2} = 72 \sqrt{3} cm^{2}$

P = $12 \sqrt{3} +12+24 = 12 \sqrt{3} +36 cm$