Question

Cine stie sa o rezolve?:)))

Answer 1

$E(x)= \frac{(x+1)^2-4}{x}: \frac{x^2-x}{x^2} \\ E(x)= \frac{(x+1+2)(x+1-2)}{x}* \frac{x^2}{x(x-1)} \\ E(x)= \frac{x*(x+3)(x-1)}{x(x-1)} \\ E(x)=x+3 \\ E(m)=5 \\ m+3=5..deci..m=2$

Answer 2

E(x)=[(x+1)²-4)/x]:(x²-x)/x²
E(x)=[(x²+2x+1-4)/x]·x²/(x²-x)   simplificam cu x
E(x)=x(x²+2x-3)/x(x-1)     simplificam cu x
E(x)=(x²+2x-3)/(x-1)
E(x)=(x-1)(x+3)/(x-1)    simplificam cu x-1
E(x)=x+3
x+3=0
x=-3

E(m)=5
E(m)=m+3
m+3=5
m=5-3
m=2