Question

Cine stie sa rezolve aceasta ecuatie exponentiala, va rog! 3 la puterea x+1=5 la puterea 2x-1

Answer 1

Foarte usor.Ai rezolvarea in poza.Daca ai neclaritati,intreab-ma!

Answer 2

$3^{x+1}=5^{2x-1} \\ \\ 3^{x}\cdot3= \frac{5^{2x}}{5} \\ \\ 3^{x}\cdot3\cdot5=5 ^{2x} \\ \\ 3^{x}\cdot15=25^{x} : \frac{1}{25^{x} } \\ \\ \frac{3^{x}}{25^{x}}= \frac{1}{15} \\ \\ {(\frac{3}{25})^{x} = \frac{1}{15}$
$x =log_{ \frac{3}{25} } ( \frac{1}{5})$