Question

Cineva bun la chimie!!! va rog ​

Answer 1

23g toluen

masa molara toluen = C7H8 = 7x12 + 8 = 84 + 8 = 92 g/mol

1mol toluen..........92g/mol

xmoli.................23g

x=> 23/93 = 0,24 moli toluen

C7H8 + Cl 2 ------------------> C7H7Cl + HCl

1 mol toluen.....1 mol clorura benzil

0,24 moli toluen.... 0,24 moli clorura benzil

sunt necesari 0,24 moli

C7H8 + 3Cl2 -------------------------C7H5Cl3 + 3HCl

1 mol toluen......3 moli clor

0,24 moli toluen.....x

x= 0,24x3 = 0,72moli Cl2

masa necesara clor = 0,72 x 71 = 51g

pt randament 75%

intrau in reactie 0,24x0,75 moli toluen = 0,18 moli toluen

C7H8 + 2Cl2----------------------------- C7H6Cl2 (clorura de benziliden) + 2 HCl

1 mol toluen...... 2 moli Cl2....... 1 mol clorura benziliden

0,18 moli toluen......y moli Cl2.......z moli clorura benziliden

z = 0,18 mol

masa clorura benziliden (o calculezi singur ) = nr moli x masa molara clorura benziliden

nr moli = 0,18 si masa molara C7H6Cl2