Question

compara:a)3^70 cu 2^105
b)7^20-6x7^19 cu49^10+48x49^9
c)2^18 cu 3^20

Answer 1

a=$3^{70} = (3^{2})^{35}=9^{35}$
b=$2^{105} =(2^{3})^{35}=8^{35}$
a>b

c=$a=7^{19}(7-6)=7^{19}$
d=$49^{9}(49+48)=(7^{2})^{9}*97=97*7^{18}$

$7^{18}*7=7^{19}$
d>c

$3^{20} \ \textgreater \ 2^{18}$