Question

Comparați numerele scriindu-le ca puteri cu aceiași baza. ​

Answer 1

Răspuns:

a) a=4^40, b=2^80;

a=4^40

a=(2^2)^40

a=2^2*40

a=2^80

a=b

4^40=2^80

b) a=3^81, b=9^40;

a=3^81

b=9^40

b=(3^2)^40

b=3^2*40

b=3^80

a>b

3^81>9^40

c) a=25^17, b=125^11;

a=25^17

a=(5^2)^17

a=5^2*17

a=5^34

b=125^11

b=(5^3)^11

b=5^3*11

b=5^33

a>b

25^17>125^11

d) a=49^16, b=7^33;

a=49^16

a=(7^2)^16

a=7^2*16

a=7^32

b=7^33

a<b

49^16<7^33

e) a=81^10, b=27^13

a=81^10

a=(3^4)^10

a=3^4*10

a=3^40

b=27^13

b=(3^3)^13

b=3^3*13

b=3^39

a>b

81^10>27^13

f) a=64^20, b=32^24

a=64^20

a=(2^6)^20

a=2^6*20

a=2^120

b=32^24

b=(2^5)^24

b=2^5*24

b=2^120

a=b

64^20=32^24

Sper ca te-am ajutat! ^^