Question

Completati,astfel incit propozitia obtinuta sa fie adevarata: a) (? - t^2)(? + t^2)=64z^2-t^4. b) (√3a - b)(? + b)=3a^2 - b^2. c) (1/2a - ?)(1/2a + ?)=?-25b^4. d) (0,3y + 2x)(? - ?)=0,09y^2-4x^2

Answer 1

Vom folosi urmatoarele formule de calcul prescurtat:

(a-b)(a+b)=a²-b²

(a±b)²=a²±2ab+b²

a)

(? - t²)(? + t²)=64z²-t⁴

(8z-t²)(8z+t²)=64z²-t⁴

b)

(√3a - b)(? + b)=3a² - b²

(√3a - b)(√3a+b)=3a² - b²

c)

$(\frac{1}{2a} -5b^2)(\frac{1}{2a}+5b^2)=\frac{1}{4a^2} -25b^4$

d)

(0,3y + 2x)(? - ?)=0,09y²-4x²

(0,3y+2x)(0,3y-2x)=0,09y²-4x²

Un alt exercitiu gasesti aici: https://brainly.ro/tema/1023163

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