Question

Compozitia procentuala elementala este : Cu ...% N=...% O= ...%
Calculati va rog frumoa compozitia procentuala​

Answer 1

Răspuns:

Azotat de cupru

Cu(NO3)2 = 64+2×(16+ 2×(14+(3×16)= 188g/mol

188gCu(NO3)2.............64gCu

100g Cu(NO3)2...............X

X=(100×64)÷188

X=43,04%Cu

188gCu(NO3)2................2×14gN

100,g....................................Y

Y =(100×2×14)÷188=14,90g%N

188gCu (NO3)2 .................2×(3×16)gO

100g Cu(NO3)2.....................Z

Z=(100×2(3×16))÷188=51,06% O