Question

concentratia procentuala si concentratia molara pt o solutie de 2,7gr de NaCl in 50 ml de apa​

Answer 1

Răspuns:

concentratia procentuala

c=mdx100/ms,      unde ms= roxvs

ms=md+m,apa

md=2,7g

la apa, ro=1g/ml, deci ms= 1g/mlx50ml=50g

ms= 2,7g+ 50g=52,7g

c= 2,7x100/52,7=5,1%

concentratia molara

c,m= niu/V(L)

niu= m/miu= 2,7g/58,5g/mol=0,046mol

V= 52,7gx1g/ml=52,7 ml= 0,0527 l    am presupus ro,s= ro,apa

c,m= 0,046mol/0,0527 l=0,87mol/l

Explicație: