Question

Concentruatia procentuala a solutiei obtinuta prin dizolvarea a 50 g SO4 × 5H2O IN 150 g apa

Answer 1

cred ca ai vrut sa scrii 50 g CuSO4 × 5H2O in 150 g apa

miu(CuSO4*5H2O) = 160 + 90 = 250 g/mol

250 g cristaloh. .............................. 160 g CuSO4

50 g ................................................... n = 32 g CuSO4

=> ms = 50 + 150 = 200 g

md = 32 g

c% = mdx100/ms = 32x100/200 = 16%