Question

Conparari fractiile din fiecare pereche :
H) 4•x+1/2•x+3 casuta 6•x+1/3•x+3
I) 11/2^n•3^n+1 casuta 7/2^n+1 •3^n
J) 4/abc barat casuta 41/abc0 barat


Ajutor
/ supra
^ la puterea

Answer 1

H)Amplificam prima fractie cu 3, iar pe a doua cu 2⇒
$\frac{12x+3}{6x+6}$ > $\frac{12x+2}{6x+6}$
I)Amplificam prima fractie cu 2 si pe a doua cu 3⇒
$\frac{22}{2 ^{n+1}*3 ^{n+1} } \ \textgreater \ \frac{21}{2^{n+1}*3 ^{n+1}}$
J) Amplificam prima fractie cu 10⇒
$\frac{40}{abc0} \ \textless \ \frac{41}{abc0}$