Question

Consideram functia f:R->R avand proprietatea f(x+1)=2x+4-f(2) , oricare ar fi x€R.
a. Arata ca f(2)=3
b. Determina legea de corespondență a functiei


urgeeeeent !!!!! DAU COROANA​

Answer 1

Răspuns:

a) f(x+1)=2x+4-f(2)

x=1

f(2)=2+4-f(2)

2^f(2)=6

f(2)=3

Si b) f(x+1)=2x+4-3 deci f(x+1)=2x+1