Question

COROANA!!! [(1,(3)-1 supra 3 ) la puterea 2 :(0,5 ) la puterea 2] :3+0,(6):1 supra 2

Answer 1

[tex] [(\frac{1}{3})^2 : (\frac{1}{2})^2] : 3+( \frac{2}{3})^2= [\frac{1}{9}: \frac{1}{4}]: 3+ \frac{4}{9} = [/tex]$[ \frac{1}{9}* \frac{4}{1}]: \frac{27}{9} + \frac{4}{9}= \frac{4}{9} : \frac{31}{9} = \frac{4}{9}* \frac{9}{31} = \frac{36}{279} =0.12$