Question

Cta face (x+3)(x-1)=(x+3)²+8

Answer 1

$(x+3)(x-1)=(x+3)^2+8 \\ x^2-x+3x-3=x^2+2*x*3+3^2+8 \\ x^2-x+3x-3=x^2+6x+9+8 \\ x^2-x^2-x+3x-6x=9+8+3 \\ -4x=20 \\ x=- \frac{20}{4} \\ x=-5$

Answer 2

x² - x + 3x - 3 = x² + 6x + 9 + 8
2x - 6x = 17 + 3
- 4x = 20
x = - 20 : 4
x = - 5