Question

Cu se rezolva 2 la puterea-3???

Answer 1

[tex]\displaystyle 2^{-3}= \frac{1}{2^3}= \frac{1}{8} \\ Obs. \\a^{-n}= \frac{1}{a^n} \\ (\frac{a}{b})^{-n}=(\frac{b}{a})^{n}[/tex]

Answer 2

2^(-3)=0,125
Sper ca te-am ajutat!