Question

Cum de face exercițiul 3la puterea 2+4+6+...20=3 la puterea n(n+1)

Answer 1

3²⁺⁴⁺⁶⁺....²⁰=3ⁿ⁽ⁿ⁺¹⁾
2+4+6+...+20=2(1+2+3+...+10)=2*10*11/2=10*11
3¹¹⁰=3ⁿ⁽ⁿ⁺¹⁾
10*11=n(n+1)
n=10