Question

cum fac 2×{3×3×11:[2×2+(3-a)×2+1]}-18=0

Answer 1

2×{3×3×11:[2×2+(3-a)×2+1]}-18=0

2×{3×3×11:[2×2+(3-a)×2+1]} = 18

3×3×11:[2×2+(3-a)×2+1] = 18 : 2

99 : [ 4 + (3 - a ) × 2 + 1] = 9

4 + (3 - a ) × 2 + 1 = 99 : 9

4 + (3 - a ) × 2 + 1 = 11

(3 - a ) × 2 = 11 - 4 - 1

(3 - a) × 2 = 6

3 - a = 6 : 2

3 - a = 3

a = 3 - 3

a = 0