Question

Cum facem la:7pe 44 plus 2 pe 33 plus 6pe 55?explicit va rog!si
repede!

Answer 1

7/44+2/33+6/55=aducem la acelasi numitor
calculam c.m.m.m.c
44=2²x11
33=3x11
55=5x11
[44,33,55]=4x5x3x11=660
660:44=15 deci cu 15 amplificam I fractie
660:33=20 a II fractie
660:55=12 a II fractie

vom avea
7/44+2/33+6/55=(7x15+2x20+6x12)/660=
=(105+40+72)/660=217/660=0,32(87)

Answer 2

7/44+2/33+6/55=aducem la acelasi numitorcalculam c.m.m.m.c44=2²x1133=3x1155=5x11[44,33,55]=4x5x3x11=660660:44=15 deci cu 15 amplificam I fractie660:33=20 a II fractie660:55=12 a II fractie
vom avea7/44+2/33+6/55=(7x15+2x20+6x12)/660==(105+40+72)/660=217/660=0,32(87)