Question

Cum pot sa calculez DVA in asa caz : x+3/x la a doua+2x + x-3/4-x la a doua?

Answer 1

(x+3)/(x²+2x+(x-3)/(4-x²)=
(x+3)/x(x+2)+(x-3)/(2-x)(2+x)=
[(x+3)(2-x)+x(x-3)]/x(4-x²)=
(2x-x²+6-3x+x²-3x)/x(4-x²)=
(-4x+6)/x(4-x²)=
cond:x≠0 si x≠2 si x≠-2
-4x+6=0
-4x=-6           ·(-1)
x=6/4
x=3/2