Question

cum rezolv asta ? ex. că nu intrleg​

Answer 1

Răspuns:

$x = ( \frac{2}{ \sqrt{12} } + \frac{9}{ \sqrt{27} } + \frac{6}{ \sqrt{108} } ) \times ( \frac{1}{ \sqrt{3} } ) {}^{ - 1} = > x = ( \frac{2}{2 \sqrt{3} } + \frac{9}{3 \sqrt{3} } + \frac{6}{6 \sqrt{3} } ) \times ( \frac{ \sqrt{3} }{1} ) {}^{1} = > ( \frac{1}{ \sqrt{3} } + \frac{3}{ \sqrt{3} } + \frac{1}{ \sqrt{3} } ) \times \frac{ \sqrt{3} }{1} = > ( \frac{ \sqrt{3} }{3} + \frac{3 \sqrt{3} }{3} + \frac{ \sqrt{3} }{3} ) \times \frac{ \sqrt{3} }{1} = > x = \frac{5 \sqrt{3} }{3} \times \frac{ \sqrt{3} }{1} = > x = \frac{5 \sqrt{3 \times \sqrt{3} } }{3} = > x = \frac{5 \times 3}{3} = > x = \frac{15}{3} = > x = 5 \\ y = (5 {}^{6} ) {}^{3} \times 25 {}^{3} \div 125 {}^{8} = > y = 5 {}^{18} \times (5 {}^{2} ) {}^{3} \div (5 {}^{3} ) {}^{8} = > y = 5 {}^{18} \times 5 {}^{6} \div 5 {}^{24} = > y = 5 {}^{24} \div 5 {}^{24} = > y = 5 {}^{1} = > y = 5 \\ ma = \frac{x + y}{2} = \frac{5 + 5}{2} = \frac{10}{2} = 5$

Coroană!!!!