Question

cum rezolv √x²+2x-3=2√3 ? daca puteti, raspundeti-mi cat mai explicit, vreau sa inteleg, va rog!

Answer 1

[tex]\sf \sqrt{x^2+2x-3}=2 \sqrt{3} \\ \sqrt{x^2-x+3x-3}=2 \sqrt{3} \\ \sqrt{x(x-1)+3(x-1)}=2 \sqrt{3} \\ \sqrt{(x+3)(x-1)}=2 \sqrt{3} \\ \sqrt{(x+3)(x-1)}= \sqrt{12} \\ (x+3)(x-1)=12 \\ x+3=6 \longrightarrow x=3 \\ x-1=2 \longrightarrow x=3 \\ \\ \boxed{ \sf Singura~varianta:x=3}[/tex]