Question

Cum se aduce la acelasi numitor doua fractii care au necunoscute?$\frac{1}{x-2} - \frac{x}{(x-2)(x+2)}$
Vreau sa-mi si explicati.

Answer 1

$\frac{1}{x-2}- \frac{1}{(x-2)(x+2)} \\ \\ = \frac{x+2}{(x-2)(x+2)} -\frac{1}{(x-2)(x+2)} \\ \\ = \frac{x+2-1}{(x-2)(x+2)} \\ \\ = \frac{x+1}{(x-2)(x+2)}$