Question

Cum se calculează (1+i√3)^2+(1-i√3)^2

Answer 1

(1+i√3)^2+(1-i√3)^2 = 1^2+2i√3 +i^2(√3)^2  + 1^2 - 2i√3 +i^2(√3)^2 =

= 1  - 1·3 +1 -1·3 = 1-3+1-3= 2 - 6 = -4