Question

cum se calculeaza raportul : x la patrat-xy+y la patrat supra lui x la patrat-y la patrat+1 ,pentru x=1+radical din 2 ,y=cu radical din 2-1

Answer 1

x=1+√2
y=√2-1
(x²-xy+y²)/(x²-y²+1)=[(1+√2)²-(1+√2)(√2-1)+(√2-1)²]/[(1+√2)²-(√2-1)²+1]=
[1+2√2+2-(√2-1+2-√2)+2-2√2+1]/[1+2√2+2-(2-2√2+1)+1]=
=(3+2√2-1+3-2√2)/(3+2√2-3+2√2+1)=
=5/(1+4√2)=5(1-4√2)/(1+32)=5(1-4√2)/33

Answer 2

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