Question

Cum se restrange $2 x^{2} +x-6$ ?

Answer 1

rezolvam ecuatia 2x²+x-6=0
Δ=1+48=49
x₁,₂=(-1+/-7)/4
x₁=(-1+7)/4=6/4=3/2
x₂=(-1-7)/4=(-8)/4=-2
 2x²+x-6=(x-x₁)(x-x₂)=(x-3/2)(x+2)=(2x-3)(x+2)

Answer 2

$2 x^{2} +x-6= \\ = (2x^{2} -8)+(x+2)= \\ =2( x^{2} -4)+(x+2)= \\ =2(x+2)(x-2)+(x+2)= \\ =(x+2)[2(x-2)+1]= \\ =(x+2)(2x-4+1)= \\ =(x+2)(2x-3).$