Question

cum se rezolvă 1+2+2la putere2+..........+2la puterea 99

Answer 1

   
[tex]\displaystyle\\ \text{Iti dau formula la cazul genral.} \\ \\ k^0+k^1+k^2+k^3+ \cdots +k^n = \boxed{\frac{k^{n+1}-1}{k-1}} \\\\ \text{Aplicam formula pentru k = 2.}\\\\ 2^0+2^1+2^2+2^3+ \cdots +2^{99} = \boxed{\frac{2^{99+1}-1}{2-1}}= \boxed{\boxed{2^{100}-1}}[/tex]