Question

Cum se rezolva : (2x-40):23=12
16:(x-1)=2
3(x-3)=9
(3·x+5·8)4=16(81-x-11):2=116
4·(x+5)=28
2·(x-5)=20

Answer 1

(2x - 40) : 23 = 12
2x - 40 = 12 * 23
2x = 276 + 40
x = 316 : 2
x = 158
16 : (x - 1) = 2
x - 1 = 2 * 16
x = 32 + 1
x = 33
3(x - 3) = 9
x - 3 = 9 : 3
x = 3 + 3
x = 6
(3x + 5 * 8)* 4 = 16
3x + 40 = 16 : 4
3x = - 40 + 4
x = - 36 : 3
x = - 12
(81 - x - 11) : 2 = 116
81 - x - 11 = 116 * 2
- x = 232 - 81 + 11
- x = 162
x = - 162
4(x + 5) = 28
x + 5 = 28 : 4
x = 7 - 5
x = 2
2(x - 5) = 20
x - 5 = 20 : 2
x = 5 + 10
x = 15