Question

cum se rezolva... 400+480:4-[680:a+4x(20+12+18)]=286

Answer 1

400+480:4-[680:a+4x(20+12+18)]=286
400+120-(680:a+4x50)=286
520-(680:a+200)=286
Notezi paranteza (680:a+200) cu "x" si obtii:
520-x=286
x=520-286
x=234
Deci 680:a+200=234
680:a=234-200
680:a=34
a=680:34
a=20