Question

cum se rezolva?
A) (12supra35-7supra20)*(-1-1supra6)=
B)(6supra32+5supra24)*30supra38-1supra8=
C)3-2:(5supra8*12supra15)+(1supra3)la puterea a2a
D)(1supra4+0,67+5supra2):0,2

Answer 1

A)
Aducem la acelasi numitor in prima paranteza :140
(12*4/140-7*7/140)*(-6-1/6)
(48-49)/140*(-7/6)
(-1/140)*(-7/6)
1/120
B)
aducem la acelasi numitor in prima paranteza:96
(18+20)/96*3/38-1/8
38/96*3/38-1/8
1/32-1/8
-3/32
C)
3-2:(1/2*1)+1/9
3-1+1/9
2+1/9
(18+1)/9
19/9
D)
(1/4+67/100+5/2)*10/2
(25+67+250)/100*5
342/100*5
324/20
171/10