Question

Cum se rezolva ecuatiile de gradul 2? 

Answer 1

$delta= b^{2} -4ac[/text] [tex]x1= \frac{-b+ \sqrt{delta} }{2a}$
$x2= \frac{-b- \sqrt{delta} }{2a}$
ex: [tex] 2x^{2} +5x+2=0 [/tex]
a=2
b=5
c=2
delta=25-16=9
$x1= \frac{-5+ \sqrt{9} }{2*2} = \frac{-5+3}{4} = \frac{-2}{4} = \frac{-1}{2}$
$x2= \frac{-5-3}{4} = \frac{-8}{4} =-2$