Question

Cum se rezolva sistemul acesta ? dau coroana
{4x-6y-2=0
{2x+3y-7=0

Answer 1

inmultesti a doua relatie cu 2 si le aduni
4x-6y-2=0
4x+6y-14=0
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8x      -16=0
8x=16
x=16:8=2
inlocuiesti x in prima relatie
8-6y-2=0
-6y+6=0
-6y=-6
y=1

Answer 2

$\left \{ {{4x-6y=2} \atop {2x+3y=7}} \right.$
$\left \{ {{4x-6y=2} \atop {4x+6y=14}} \right.$
[tex] \left \{ {{4x-6y=2} \atop {8x=16}} \right. [/tex]
$\left \{ {{x=2} \atop {8-6y=2}} \right.$
$\left \{ {{x=2} \atop {-6y=-6}} \right.$
$\left \{ {{x=2} \atop {y=1}} \right.$