Question

d ) 18 la puterea 2 +36÷[2la puterea 64÷(2la puterea9) totul la puterea 7 +9 la puterea 15÷(3×3la puterea 28)] . VA ROG AJUTATIMA DAU COROANA 5 PUNCTE SI UN MULTUMESC . VA ROG MULT :-(

Answer 1

D ) 18^2 +36 :[2^64 :(2^9)^7 +9^15 :(3×3^28)]=
= 2^2x3^4 +2^2x3^2 :(2^64 :2^63 +3^30 :3^29)=
= 2^2x3^4 +2^2x3^2 :(2 +3)=
= 2^2x3^4 +2^2x3^2 :5=
= 2^2x3^2(3^2+1/5)=
= 4x9x(9+1/5)=
=36x(45+1)/5=
=36x46/5=
=1656/5=
=331,2