Question

D) [3^48÷3^18+(2^4) ^5+6^23÷6^13]÷[(3^5) ^2×(2^2) ^5+3^17×3^13+(2^5) ^4]

Answer 1

Răspuns:

1

Explicație pas cu pas:

[3^48÷3^18+(2^4) ^5+6^23÷6^13]÷[(3^5) ^2×(2^2) ^5+3^17×3^13+(2^5) ^4] =

[3^(48-18)+2^20 + 6^(23-13)] : [ 3^10 × 2^10 + 3^(17+13) + 2^20] =

(3^30 + 2^20 + 6^10) : [ (3×2)^10 + 3^30 + 2^20] =

(3^30 + 2^20 + 6^10) : (6^10 + 3^30 + 2^20) =

(3^30 + 2^20 + 6^10) : (3^30 + 2^20 + 6^10) =

= 1

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Answer 2

Răspuns:

Explicație pas cu pas: