Question

d) (3 la puterea 4) la puterea 9 : (9 la puterea 6) la puterea 3

e)(11 la puterea 2011 • 4 la puterea 1005) : [( 22la puterea 2)la puterea 5]la puterea 201

VA ROG,REPEDE!!!

Answer 1

(3⁴)⁹ : (9⁶)³ = 3⁴ˣ⁹ : (3²)⁶ˣ³ = 3³⁶ : 3²ˣ¹⁸ = 3³⁶⁻³⁶ = 3⁰ = 1

(11²⁰¹¹ ·4¹⁰⁰⁵) :[(22²)⁵]²⁰¹ = [11²⁰¹¹·(2²)¹⁰⁰⁵] :[(11x2)²]⁵ˣ²⁰¹ =

= (11²⁰¹¹·2²⁰¹⁰):[(11²ˣ¹⁰⁰⁵)·(2²ˣ¹⁰⁰⁵) = (11²⁰¹¹·2²⁰¹⁰):(11²⁰¹⁰·2²⁰¹⁰) =

= 11²⁰¹¹⁻²⁰¹⁰·2²⁰¹⁰⁻²⁰¹⁰) = 11¹·2⁰ = 11