Question

Daca 2a+b=2 , calculati valoarea numarului
 n = ( 4a + 2b ) + $( 6a + 3b )^{2}$ + $( 8a + 4b )^{3}$

Answer 1

[tex](4a+2b)+ (6a+3b)^{2}+ (8a+4b)^{3}= [/tex]
[tex]2(2a+b)+ [3(2a+b)]^{2} + [4(2a+b)]^{3}=2*2+9*4+ 64*8= [/tex]
$4+36+512=550$