Question

Daca 2apatrat+25bpatrat+5(2a+5)-10ab=0, determinati a si b

Answer 1

2a^2+25b^2+5(2a+5)-10ab=0 <=> (a^2+10a+25)+(a^2-10ab+25b^2)=0 <=> (a+5)^2+(a-5b)^2=0 <=> a-5=0 si a-5b=0 <=> a=5 si b=a/5=1.

In concluzie, a=5 si b=1.