Question

Daca 2x-y=6 si 4x²-y²=30, calculati valoarea numarului:
n=(2x+y)+(2x+y)²+(2x+y)³+(2x+y)⁴​

Answer 1

2x-y=6

4x²-y²=30

(2x+y)(2x-y)=30

(2x+y)×6=30

2x+y=30:6

2x+y=5

n=(2x+y)+(2x+y)²+(2x+y)³+(2x+y)⁴

n=5+5²+5³+5⁴

n=5+25+125+625

n=780