Question

Daca (3-y) la 2 este mai mic sau egal decat 0 , atunci y= -3

Answer 1

$(3-y)^{2}\leq 0\\9-6y+y^{2}\leq 0\\y^{2}-6y+9\leq 0$

Δ = (-6)^2 -4*1*9 = 36 - 36 = 0

$y=\frac{6}{2}=3$

Verificare:

y^2 - 6y + 9 ≤ 0

9 - 18 + 9 ≤ 0

0 ≤ 0 adevarat