Question

Daca  4x + $\frac{3}{8x} =6$ , atunci 16x² + $\frac{9}{ 64x^{2} }$ este egal cu : ..... 

Answer 1

$\frac{3}{8x} =6$⇒48x=3⇒x=$\frac{1}{16}$

16x²+$\frac{9}{64 x^{2} }=16* \frac{1}{16 ^{2} }+$$\frac{9}{64* \frac{1}{16 ^{2} } }= \frac{1}{16}+ \frac{9}{16*4* \frac{1}{16 ^{2} } }$=
=$\frac{1}{16}+ \frac{9}{ \frac{1}{4} }= \frac{1}{16}+36= \frac{1}{16}+ \frac{576}{16}= \frac{577}{16}$

Answer 2

4x+3/8x=6    ridicam la patrat
16x²+2(4x × 3/8x)+9/64x²=6²
16x²+3+9/64x²=36
16x²+9/64x²=36-3
16x²+9/64x²=33