Question

Daca a/11=b/3, calculati 7a-2b/3a+5b va rog sa ma ajutati daca puteti.

Answer 1

a/11=b/3=k

a=11k
b=3k

(7a-2b)/(3a+5b)= (7*11k-2*3k)/(3*11k+5*3k)=

=(77k-6k)/(33k+15k)=

=71k/48k=

=71/48

Answer 2

Daca a/11=b/3, calculati 7a-2b/3a+5b

$\frac{a}{11}= \frac{b}{3} \\ => \frac{a}{b}= \frac{11}{3}$

$\frac{7a-2b}{3a+5b} .simplificam.fortat.cu.b \\ \frac{7 \frac{a}{b} -2 \frac{b}{b}}{3\frac{a}{b}+5\frac{b}{b}} =\frac{7 \frac{a}{b} -2 }{3\frac{a}{b}+5}=\frac{7 \frac{11}{3} -2 }{3\frac{11}{3}+5}=\frac{ \frac{77}{3} - \frac{6}{3} }{11+5}= \frac{ \frac{71}{3}}{16}= \frac{71}{3*16}= \frac{71}{48}$