Question

daca a×b=27,a×c=45 si b×c=15,aflati numerele naturale a,b si c​

Answer 1

a×b=27

a×c=45

b×c=15

b=27/a

c=45/a

27/a*45/a=15

1215/a²=15

a²*15=1215

a²=1215/15

a²=81

a=√81

a=9

b=27/a=27/9=3

c=45/a=45/9=5