Question

Daca
E(x)=2$x^{3}$ - 3$x^{2}$ - 3x + 6
E($\sqrt{2}$)

Answer 1

$E( \sqrt{2} )=2* (\sqrt{2})^3-3* (\sqrt{2})^2-3 \sqrt{2}+6=4 \sqrt{2}-6-3\sqrt{2}+6 = \sqrt{2}$