Question

Daca faceti CORECT PRIMITI 30 de PUNCTE!!
CAlculati: (2^4)^4:2^2^4*(3^2-1)-2010^0*2^2 trebuie sa dea 4 fara rest m-am uitat la sfarsitul cartii!!

Answer 1

=(2⁴)⁴ :2¹⁶ ·( 3² -1 ) - 2010 °· 2² =                         a°=1
= 2¹⁶ :2 ¹⁶· ( 9 - 1)  -   1  ·  4 = 
= 2¹⁶ ⁻¹⁶ · 8   - 4 =
= 2° · 8 -4 = 8 - 4 = 4 

Answer 2

$(2^4)^4: 2^{ 2^{4} } *(3^2-1)-2010^0*2^2=2^1^6:2^1^6*(9-1)-1*4= \\ =2^1^6^-^1^6*8-1*4=2^0*8-1*4=1*8-1*4=8-4=4$