Question

Daca impartim suma a doua nr la diferenta lor,obtinem catul 1 si restul 12.daca adunam cu diferenta lor,obtinem 64.care sunt cele doua numere.

Answer 1

(a+b):(a-b)=1 rest 12=> a+b= 1*(a-b)+12=>a+b=(a-b)+12 (a+b)+(a-b)=64 Avem acum a+b=(a-b)+12 in ecuatie vom inlocui (a-b)+12+(a-b)=64 (a-b)+(a-b)=64-12 2(a-b)=52 a-b=52:2 a-b=26 a+b=(a-b)+12 Si a-b=26=> a+b=26+12=>a+b=38 Avem a-b=26 a+b=38 se face sistem 2a=26+38 2a=64=>a=64:2=>a=32 a-b=26 si a=32 32-b=26=>b=32-26=>b=6