Question

Dacă poate cineva? Dau 50 puncte ​

Answer 1

Daca A(x,y) apartine lui Gf => f(x) = y

7. f(x) = 2x +m

A(2,5) => f(2) = 5 => 2*2 +m = 5 => 4 + m = 5 => m = 1

B(m,9) => f(m) = 9 => 2m + m = 9 => 3m = 9 => m = 3

C(1,2m) => f(1) =2m => 2 + m = 2m => m = 2

D(m+1 , -m-patrat) => f(m+1) = 2m + 2 + m = -m patrat => m-patrat -3m + 2 = 0 => m = -1 si -2

8. f(x) = ax + b

f(-1) = 3 => -a + b = 3

f(1) = 1 => a+ b = 3

adunam => 2b = 6 => b = 3 => a = 0

f(-2) = 5 => -2a +b = 5 => -2a = 4 => a = -2

f(0) = 1 => b = 1

f(1) = 4 => a+b = 4

f(-2) = 7 => -2a + b = 7

scadem => 3a = -3  => a=  -1 => b = 5

rad2 a + b = 1

a + b = rad 2

=> a (rad2 -1) = 1 - rad2 => a = -1

b = 1 + rad2