Question

Daca se imparte suma a cinci numere consecutive la 4,se obtine catul 32 si restul 2. Sa se afle cele cinci numere.

Answer 1

(a+a+1+a+2+a+3+a+4):4=32 rest2
(5a+10):4=32 rest 2
conform teoremei impartirii cu rest avem
5a+10=32*4+2
5a+10=130
5a=130-10
5a=120
a=120:5
a=24
numerele sunt 24,25,26,27,28

Answer 2

(a+a+1+a+2+a+3+a+4):4=32r2
(5a+10):4=32r2
5a+10=4x32+2
5a=130-10
a=120:5
a=24
nr sunt 24,25,26,27,28