Question

Daca x=3radical5 calculeaza:  a) (x la a doua+x-2)la a doua - x la a doua (x la a doua +1)+3(x-3= ; b) (x la a doua+x+1)la a doua-(x la a doua+1)(x la a doua-1)-9(x+3)(x-3=                                                                                                                                                                

Answer 1

a)  [(3√5)^2+3√5-2]^2-[(3√5)^2+1]+3(3√5-3)=
43^2+258√5+45-46+9√5-9=
1849+249√5-10=1839+249√5

B)  = .........= 2x^3-6x^2+2x+81=

=54*5-6*9*5+6√5+81=.......=6√5+81