Question

daca x supra y = 3 supra 5 atunci 4x+3y supra 2x-y =....​

Answer 1

Răspuns:

x/y=3/5=>x=3y/5

(4x+3y)/2x-y)=

[(4·3y/5+3y)] / [(2·3y/5-y)]=

(12y/5+⁵⁾3y) /(6y/5-⁵⁾y)=

27y/5:y/5=

27y/5·5/y=

27y/y=27

Answer 2

x/y=3/5 => x=3y/5

(4x+3y)/(2x-y)

=(4*3y/5+3y)/(2*3y/5-y)

=(12y/5+3y)/(6y/5-y)

=(12y/5+15y/5)/(6y/5-5y/5)

=(27y/5)/(y/5)

=27y/5*5/y

=27

Kawaiimath