Question

Daca {x,y,z}d.p{1,2,3}, x+y+z=24
Aflați x,y,z

Answer 1

x/1 = y/2 = z/3 = k
x=k
y=2k
z=3k
____ "+"
6k=24 =>k=4
x=4
y=8
z=12

Answer 2

[x, y, z ] d.p [ 1, 2, 3 ],    x + y + z = 24

x / 1 = y / 2 = z / 3 = k ⇒  x = k;    y = 2 k   si   z = 3 k

k + 2 k + 3 k = 24

6 k = 24

k = 24 : 6 ⇒   k = 4

x = 4

y = 2 × 4 = 8

y = 3 × 4 = 12

Verific:   x + y + z = 4 + 8 + 12 = 24